Integrand size = 21, antiderivative size = 290 \[ \int \frac {\left (b x^2+c x^4\right )^{3/2}}{x^{5/2}} \, dx=\frac {8 b^2 x^{3/2} \left (b+c x^2\right )}{15 \sqrt {c} \left (\sqrt {b}+\sqrt {c} x\right ) \sqrt {b x^2+c x^4}}+\frac {4}{15} b \sqrt {x} \sqrt {b x^2+c x^4}+\frac {2 \left (b x^2+c x^4\right )^{3/2}}{9 x^{3/2}}-\frac {8 b^{9/4} x \left (\sqrt {b}+\sqrt {c} x\right ) \sqrt {\frac {b+c x^2}{\left (\sqrt {b}+\sqrt {c} x\right )^2}} E\left (2 \arctan \left (\frac {\sqrt [4]{c} \sqrt {x}}{\sqrt [4]{b}}\right )|\frac {1}{2}\right )}{15 c^{3/4} \sqrt {b x^2+c x^4}}+\frac {4 b^{9/4} x \left (\sqrt {b}+\sqrt {c} x\right ) \sqrt {\frac {b+c x^2}{\left (\sqrt {b}+\sqrt {c} x\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{c} \sqrt {x}}{\sqrt [4]{b}}\right ),\frac {1}{2}\right )}{15 c^{3/4} \sqrt {b x^2+c x^4}} \]
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Time = 0.19 (sec) , antiderivative size = 290, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.286, Rules used = {2046, 2057, 335, 311, 226, 1210} \[ \int \frac {\left (b x^2+c x^4\right )^{3/2}}{x^{5/2}} \, dx=\frac {4 b^{9/4} x \left (\sqrt {b}+\sqrt {c} x\right ) \sqrt {\frac {b+c x^2}{\left (\sqrt {b}+\sqrt {c} x\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{c} \sqrt {x}}{\sqrt [4]{b}}\right ),\frac {1}{2}\right )}{15 c^{3/4} \sqrt {b x^2+c x^4}}-\frac {8 b^{9/4} x \left (\sqrt {b}+\sqrt {c} x\right ) \sqrt {\frac {b+c x^2}{\left (\sqrt {b}+\sqrt {c} x\right )^2}} E\left (2 \arctan \left (\frac {\sqrt [4]{c} \sqrt {x}}{\sqrt [4]{b}}\right )|\frac {1}{2}\right )}{15 c^{3/4} \sqrt {b x^2+c x^4}}+\frac {8 b^2 x^{3/2} \left (b+c x^2\right )}{15 \sqrt {c} \left (\sqrt {b}+\sqrt {c} x\right ) \sqrt {b x^2+c x^4}}+\frac {4}{15} b \sqrt {x} \sqrt {b x^2+c x^4}+\frac {2 \left (b x^2+c x^4\right )^{3/2}}{9 x^{3/2}} \]
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Rule 226
Rule 311
Rule 335
Rule 1210
Rule 2046
Rule 2057
Rubi steps \begin{align*} \text {integral}& = \frac {2 \left (b x^2+c x^4\right )^{3/2}}{9 x^{3/2}}+\frac {1}{3} (2 b) \int \frac {\sqrt {b x^2+c x^4}}{\sqrt {x}} \, dx \\ & = \frac {4}{15} b \sqrt {x} \sqrt {b x^2+c x^4}+\frac {2 \left (b x^2+c x^4\right )^{3/2}}{9 x^{3/2}}+\frac {1}{15} \left (4 b^2\right ) \int \frac {x^{3/2}}{\sqrt {b x^2+c x^4}} \, dx \\ & = \frac {4}{15} b \sqrt {x} \sqrt {b x^2+c x^4}+\frac {2 \left (b x^2+c x^4\right )^{3/2}}{9 x^{3/2}}+\frac {\left (4 b^2 x \sqrt {b+c x^2}\right ) \int \frac {\sqrt {x}}{\sqrt {b+c x^2}} \, dx}{15 \sqrt {b x^2+c x^4}} \\ & = \frac {4}{15} b \sqrt {x} \sqrt {b x^2+c x^4}+\frac {2 \left (b x^2+c x^4\right )^{3/2}}{9 x^{3/2}}+\frac {\left (8 b^2 x \sqrt {b+c x^2}\right ) \text {Subst}\left (\int \frac {x^2}{\sqrt {b+c x^4}} \, dx,x,\sqrt {x}\right )}{15 \sqrt {b x^2+c x^4}} \\ & = \frac {4}{15} b \sqrt {x} \sqrt {b x^2+c x^4}+\frac {2 \left (b x^2+c x^4\right )^{3/2}}{9 x^{3/2}}+\frac {\left (8 b^{5/2} x \sqrt {b+c x^2}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {b+c x^4}} \, dx,x,\sqrt {x}\right )}{15 \sqrt {c} \sqrt {b x^2+c x^4}}-\frac {\left (8 b^{5/2} x \sqrt {b+c x^2}\right ) \text {Subst}\left (\int \frac {1-\frac {\sqrt {c} x^2}{\sqrt {b}}}{\sqrt {b+c x^4}} \, dx,x,\sqrt {x}\right )}{15 \sqrt {c} \sqrt {b x^2+c x^4}} \\ & = \frac {8 b^2 x^{3/2} \left (b+c x^2\right )}{15 \sqrt {c} \left (\sqrt {b}+\sqrt {c} x\right ) \sqrt {b x^2+c x^4}}+\frac {4}{15} b \sqrt {x} \sqrt {b x^2+c x^4}+\frac {2 \left (b x^2+c x^4\right )^{3/2}}{9 x^{3/2}}-\frac {8 b^{9/4} x \left (\sqrt {b}+\sqrt {c} x\right ) \sqrt {\frac {b+c x^2}{\left (\sqrt {b}+\sqrt {c} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} \sqrt {x}}{\sqrt [4]{b}}\right )|\frac {1}{2}\right )}{15 c^{3/4} \sqrt {b x^2+c x^4}}+\frac {4 b^{9/4} x \left (\sqrt {b}+\sqrt {c} x\right ) \sqrt {\frac {b+c x^2}{\left (\sqrt {b}+\sqrt {c} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} \sqrt {x}}{\sqrt [4]{b}}\right )|\frac {1}{2}\right )}{15 c^{3/4} \sqrt {b x^2+c x^4}} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 10.01 (sec) , antiderivative size = 58, normalized size of antiderivative = 0.20 \[ \int \frac {\left (b x^2+c x^4\right )^{3/2}}{x^{5/2}} \, dx=\frac {2 b \sqrt {x} \sqrt {x^2 \left (b+c x^2\right )} \operatorname {Hypergeometric2F1}\left (-\frac {3}{2},\frac {3}{4},\frac {7}{4},-\frac {c x^2}{b}\right )}{3 \sqrt {1+\frac {c x^2}{b}}} \]
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Time = 0.18 (sec) , antiderivative size = 226, normalized size of antiderivative = 0.78
method | result | size |
default | \(\frac {2 \left (c \,x^{4}+b \,x^{2}\right )^{\frac {3}{2}} \left (5 c^{3} x^{6}+12 b^{3} \sqrt {\frac {c x +\sqrt {-b c}}{\sqrt {-b c}}}\, \sqrt {2}\, \sqrt {\frac {-c x +\sqrt {-b c}}{\sqrt {-b c}}}\, \sqrt {-\frac {x c}{\sqrt {-b c}}}\, E\left (\sqrt {\frac {c x +\sqrt {-b c}}{\sqrt {-b c}}}, \frac {\sqrt {2}}{2}\right )-6 b^{3} \sqrt {\frac {c x +\sqrt {-b c}}{\sqrt {-b c}}}\, \sqrt {2}\, \sqrt {\frac {-c x +\sqrt {-b c}}{\sqrt {-b c}}}\, \sqrt {-\frac {x c}{\sqrt {-b c}}}\, F\left (\sqrt {\frac {c x +\sqrt {-b c}}{\sqrt {-b c}}}, \frac {\sqrt {2}}{2}\right )+16 b \,c^{2} x^{4}+11 b^{2} c \,x^{2}\right )}{45 x^{\frac {7}{2}} \left (c \,x^{2}+b \right )^{2} c}\) | \(226\) |
risch | \(\frac {2 \sqrt {x}\, \left (5 c \,x^{2}+11 b \right ) \sqrt {x^{2} \left (c \,x^{2}+b \right )}}{45}+\frac {4 b^{2} \sqrt {-b c}\, \sqrt {\frac {\left (x +\frac {\sqrt {-b c}}{c}\right ) c}{\sqrt {-b c}}}\, \sqrt {-\frac {2 \left (x -\frac {\sqrt {-b c}}{c}\right ) c}{\sqrt {-b c}}}\, \sqrt {-\frac {x c}{\sqrt {-b c}}}\, \left (-\frac {2 \sqrt {-b c}\, E\left (\sqrt {\frac {\left (x +\frac {\sqrt {-b c}}{c}\right ) c}{\sqrt {-b c}}}, \frac {\sqrt {2}}{2}\right )}{c}+\frac {\sqrt {-b c}\, F\left (\sqrt {\frac {\left (x +\frac {\sqrt {-b c}}{c}\right ) c}{\sqrt {-b c}}}, \frac {\sqrt {2}}{2}\right )}{c}\right ) \sqrt {x^{2} \left (c \,x^{2}+b \right )}\, \sqrt {x \left (c \,x^{2}+b \right )}}{15 c \sqrt {c \,x^{3}+b x}\, x^{\frac {3}{2}} \left (c \,x^{2}+b \right )}\) | \(227\) |
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.08 (sec) , antiderivative size = 62, normalized size of antiderivative = 0.21 \[ \int \frac {\left (b x^2+c x^4\right )^{3/2}}{x^{5/2}} \, dx=-\frac {2 \, {\left (12 \, b^{2} \sqrt {c} {\rm weierstrassZeta}\left (-\frac {4 \, b}{c}, 0, {\rm weierstrassPInverse}\left (-\frac {4 \, b}{c}, 0, x\right )\right ) - \sqrt {c x^{4} + b x^{2}} {\left (5 \, c^{2} x^{2} + 11 \, b c\right )} \sqrt {x}\right )}}{45 \, c} \]
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\[ \int \frac {\left (b x^2+c x^4\right )^{3/2}}{x^{5/2}} \, dx=\int \frac {\left (x^{2} \left (b + c x^{2}\right )\right )^{\frac {3}{2}}}{x^{\frac {5}{2}}}\, dx \]
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\[ \int \frac {\left (b x^2+c x^4\right )^{3/2}}{x^{5/2}} \, dx=\int { \frac {{\left (c x^{4} + b x^{2}\right )}^{\frac {3}{2}}}{x^{\frac {5}{2}}} \,d x } \]
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\[ \int \frac {\left (b x^2+c x^4\right )^{3/2}}{x^{5/2}} \, dx=\int { \frac {{\left (c x^{4} + b x^{2}\right )}^{\frac {3}{2}}}{x^{\frac {5}{2}}} \,d x } \]
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Timed out. \[ \int \frac {\left (b x^2+c x^4\right )^{3/2}}{x^{5/2}} \, dx=\int \frac {{\left (c\,x^4+b\,x^2\right )}^{3/2}}{x^{5/2}} \,d x \]
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